FAQ

Java

JSP

Servlet


Advertisement



How to List Files and Subdirectories in a Directory?

Here an example uses File class to retrive all files and subdirectories under the root.

  public static void main(String[] argv){
File dir = new File("c:\\");
String[] children = dir.list();
if (children != null) {
for (String filename: children) {
out.println(filename);
}
}
else {
out.println("No File Found.");
}
}

Here is an example showing how to return subdirectories only. From java.io.File Java API doc, a list of files can also be retrieved as array of File objects.

class DirectoryFileFilter implements FileFilter
{
public boolean accept(File file) {
return file.isDirectory();
}
}
public class ListSubdirectory {
public static void main(String[] argv){

File dir = new File("c:\\");
File[] files = dir.listFiles(new DirectoryFileFilter());
if (files != null) {
for (File file: files) {
out.println(file.getName());
}
}
else {
out.println("No Subdirectory Found.");
}
}
}

Here is an example to retrive a set of document file which given file extensions.

class MyDocFileFilter implements FileFilter
{
private final String[] myDocumentExtensions
= new String[] {".txt", ".doc", ".html", "htm"};

public boolean accept(File file) {

if (!file.isFile())
return false;

for (String extension : myDocumentExtensions) {
if (file.getName().toLowerCase().endsWith(extension))
return true;
}
return false;
}
}

public class ListMyDocuments {

public static void main(String [] argv){
File dir = new File("c:\\");
File[] files = dir.listFiles(new MyDocFileFilter());
if (files != null) {
for (File file: files) {
out.println(file.getName());
}
}
else {
out.println("No File Found.");
}
}

}


Printer-friendly version Printer-friendly version | Send this 
article to a friend Mail this to a friend

Previous Next vertical dots separating previous/next from contents/index/pdf Contents

  |   |